Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval if #f(x) = 2x^2 − 3x + 1# and [0, 2]?
1 Answer
Apr 2, 2015
The Mean Value Theorem says that
if a function
then there exists a value
(The right hand side of this is often referred to as the secant).
For the given function
If we (temporarily) assume the Mean Value Theorem holds then there must be a value
which solves as
Testing this back in the equation of the Mean Value Theorem demonstrates that the theorem holds for the given equation.