# Does zinc react with sodium hydroxide?

Jun 11, 2017

Yes to form the zincate, ${\left[Z n {\left(O H\right)}_{4}\right]}^{2 -}$

#### Explanation:

$Z n + 4 H {O}^{-} \rightarrow {\left[Z n {\left(O H\right)}_{4}\right]}^{2 -} + 2 {e}^{-}$

And since zinc is oxidized, something must be reduced........

${H}_{2} O + {e}^{-} \rightarrow \frac{1}{2} {H}_{2} \left(g\right) + H {O}^{-}$

Overall,.............

$Z n \left(s\right) + 2 H {O}^{-} + 2 {H}_{2} O \left(l\right) \rightarrow {\left[Z n {\left(O H\right)}_{4}\right]}^{2 -} + {H}_{2} \left(g\right)$

which is balanced with respect to mass and charge, as required.