Double angle formula question... Can I please get some help?

Question

#sin theta = (2sqrt2)/3 and pi/2 <0<pi# Find tan #2theta#

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Answer 1 · 2018-04-06T12:28:00

#=(4sqrt(2))/7#

#tantheta=-2sqrt(2)# for #pi/2< theta< pi#

#tan2theta=(2tantheta)/(1-tan^2theta)#

#=(2(-2sqrt(2)))/(1-(-2sqrt(2))^2)#

#=(-4sqrt(2))/(1-8)#

#=(-4sqrt(2))/(-7)#

#=(4sqrt(2))/7#