Doubt in Law of equivalents?
According to law of equivalents, number of gram equivalents of all reactants (none of them in excess) = number of gram equivalents of all products if all reactants undergo the reaction.
Are there any conditions/exceptions under which the law does not hold?
I noticed a difference in a mixture solution. The
equivalents add up.
For example this problem: When a mixture of (NaBr) and (NaCl) is repeatedly digested with (H_2SO_4, all the halogens are expelled and (Na_2SO_4) is formed quantitatively. With a particular mixture, it was found that the weight of (Na_2SO_4) obtained was precisely the same as the weight of (NaBr,NaCl) mixture taken. Calculate the ratio of (NaCl) and (NaBr) in the mixture.
I could comfortably solve this question using mole concept and POAC but the solution I have uses equivalent concept and I didn't understand this step:
Number of equivalents of (NaCl) + Number of equivalents of (NaBr) = Number of equivalents of (Na_2SO_4).
According to law of equivalents, number of gram equivalents of all reactants (none of them in excess) = number of gram equivalents of all products if all reactants undergo the reaction.
Are there any conditions/exceptions under which the law does not hold?
I noticed a difference in a mixture solution. The
equivalents add up.
For example this problem: When a mixture of (NaBr) and (NaCl) is repeatedly digested with (H_2SO_4, all the halogens are expelled and (Na_2SO_4) is formed quantitatively. With a particular mixture, it was found that the weight of (Na_2SO_4) obtained was precisely the same as the weight of (NaBr,NaCl) mixture taken. Calculate the ratio of (NaCl) and (NaBr) in the mixture.
I could comfortably solve this question using mole concept and POAC but the solution I have uses equivalent concept and I didn't understand this step:
Number of equivalents of (NaCl) + Number of equivalents of (NaBr) = Number of equivalents of (Na_2SO_4).
1 Answer
Well mass is conserved in EVERY chemical reaction....
Explanation:
And this has been the observation of centuries of research and endeavour...
And here, you certainly got a FINITE mass of sodium ion... And you propose to isolate this as sodium sulfate. And so because the molar quantity of
And the molar quantity of
Anyway, if you gots an objection, or a query, or a speculation, feel free to post it, and someone will attempt to muddy the waters...