During one NRL season, the Melbourne Storm won 16 out of 22 games. What percentage of games did the Storm lose?

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2 Answers
Jun 3, 2018

They lost 27.28% of the games.

Explanation:

To find the percentage of the games they lost, you first have to find the percentage of the games they won.

Find the percentage of the games they won:

16/22*100=72.72%

Then subtract the amount of games they won from 100%. This is because you want to find the amount of games they lost out of all the games they played (i.e. 100%).

100%-72.72%=27.28%

Therefore, they won 72.72% of the time and lost 27.28% of the time.

Jun 3, 2018

27.3%

Explanation:

If the Storms won 16 out of 22 games, they must have lost the other 6 games.

So the question is: what percent of 22 is 6?

To turn that question into an equation, here are some helpful tips:

  1. "Is" means "equals", so wherever you see "is", use a = sign.
  2. "Of" means "multiplication", so use a xx sign when you see that word.
  3. Use variables for the things you do not know. Since the percent is not known, I will call it x.
  4. A percent of a number is the same as that number over 100. Since the percent is not known, it will be represented by x/100

stackrel(x/100)overbrace"What percent"stackrel(xx)overbrace"of"stackrel(22)overbrace"22"stackrel(=)overbrace"is"stackrel(6)overbrace"6"

x/100 xx 22 = 6

x/100 = 6 -:22

x/100 = 0.bar(27)

x = 27.bar(27)% = 27.3%

The Storms lost 27.3% of their games.