# Elemental S reacts with O2 to form SO3 according to the reaction 2S+3O2→2SO3 Part B: What is the theoretical yield of SO3 produced by the quantities described in Part A? Express your answer numerically in grams.

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Part A: 1.88x10^23 O2 molecules are needed to react with 6.67 g of S.

Part A: 1.88x10^23 O2 molecules are needed to react with 6.67 g of S.

##### 2 Answers

We address the equation...

#### Explanation:

The question specifies that we got

But we gots with respect to sulfur,

And a bit of arithmetic later, we establish that we got stoichiometric quantities of dioxygen, and sulfur….in the reaction we produce a mass of ………..

Note that when

The industrial sulfur cycle must be a dirty, smelly, unfriendly process. The process is undoubtedly necessary to support our civilization....

#### Explanation:

Numerical relationships between coefficients of the equation suggest the following conversion factors:

#(n("SO"_3))/(n("O"_2)) = 2/3# #(n("SO"_3))/(n("S")) = 2/2 = 1#

From part A:

Where

Apply the conversion factor between

As a side note: in cases that the formula mass of sulfur,