# Enter the measure of an exterior angle of a regular pentagon?

Sep 12, 2016

${72}^{\circ}$
We know that for any polygon, the sum of all exterior angles is ALWAYS equal to ${360}^{\circ}$.
For a regular polygon, the size of EACH exterior angle can be determined by dividing $360$ by the number of sides of polygon or number of angles.
$\therefore$ All exterior angles of a regular pentagon$= \frac{360}{5} = {72}^{\circ}$