Evaluate #5/x(x+8)^2# for #x=-4#?

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Answer 1 · 2018-04-27T02:43:42

#-5/4(-4+8)^2=color(blue)(-20#

Given:

#5/x(x+8)^2#, where #x=-4#

Follow the order of operations as indicated by PEMDAS.

P arentheses/brackets

E xponents/radicals

M ultiplication and D ivision in order from left to right.

A ddition and S ubtraction in order from left to right.

Substitute #-4# for #x#.

#5/(-4)(-4+8)^2#

Simplify.

#-5/4(-4+8)^2#

Simplify #-4+8# to #4#.

#-5/4(4)^2#

Simplify #4^2# to #16#.

#-5/4xx16#

Simplify #-5/4xx16# to #-80/4#

#-80/4#

Simplify #-80/4# to #-20#.

#-20#