How do I evaluate the indefinite integral inttan^2(x)dx ?
1 Answer
Jul 30, 2014
=tanx-x+c , wherec is a constantUsing Trigonometric Identity, which is
sec^2x-tan^2x=1
tan^2x=sec^2x-1 Using this Trigonometric Identity in integration,
=int(sec^2x-1)dx
=intsec^2xdx-intdx
=tanx-x+c , wherec is a constant