F(x)=\sqrt(x^(2)-5x+6), find the domain and range ?

1 Answer
Jun 24, 2018

Domain: #x in(-oo,2]uu[3,oo)#, Range: #yin[0,oo)#

Explanation:

To find the domain, we will factor the quadratic expression in the square root to get #F(x)=sqrt((x-2)(x-3))#.

Assuming #F:RR->RR#, we know that #(x-2)(x-3)>=0#. Consider #x<2#: we have #("negative")("negative")="positive">=0#.
Consider #2< x <3#: we have #("positive")("negative")="negative"<0#.
Consider #x>3#: we have #("positive")("positive")="positive">=0#.
Therefore, the domain of #F# is #x in (-oo, 2]uu[3,oo)#.

For the range of #F#, we know that the square root function returns non-negative numbers so we know that the range of #F# is #yin[0,oo)#.