# F(x)=(x^2-2x+4)/ (x-2), f' (x)=(x^2-4x)/(x-2)^2 , f'' (x)=8/(x-2)^3 How to find the domain of f(x), x and y-intercepts, vertical asymptotes, the critical numbers, concave up and down and Sketch graph ?

##### 1 Answer

Apr 16, 2015

Have a look:

graph{(x^2-2x+4)/(x-2) [-46.25, 46.24, -23.1, 23.15]}