F(x)=(x+5)^3-2 how can graph by using shifting, compressing,​ stretching, and/or reflecting? Can you let me know the steps?

1 Answer
Jan 28, 2018

See below

Explanation:

I'm presuming that the equation is #f(x) = (x+5)^3 -2#.
1)
There is no stretch because there is no number in front so that means it just 1. (Eg. if theres a 2 in the front the whole function #f(x)= 2(x+5)^3 -2#, then it stretches 2times, but theres no number in this case so its just 1

2)
There is also no compression because there is no number infront of the #x#. (Eg. If theres a 2 infront of x, #f(x)= (2x+5)^3 -2# then the graph compress 2 times, but in this case theres none).

3)
Just remember that everything inside the brackets is the horizontal shift and to know which direction just set the it to zero, #(x+5) =0# then solve to get #x=-5# which means your graph will move horizontally to the left(negative).

4)
The number outside the brackets is usually the vertical shift
In this case its the #-2#, meaning that your parabola would move down 2 units.

5)
To double check if your graph is write go to www.desmos.com and type the formula and it should show you what it looks like.