# FCS # y = tan_(fcs)( x; -1 ) = tan ( x -tan(x- tan ( x - ...#. How do you prove that, piecewise, at y = 1, the tangent is inclined at #33^o 41' 24'' # to the x-axis, nearly?

##### 1 Answer

Jul 3, 2018

See explanation and the wholesome Socratic graph.

#### Explanation:

The FCS generator is

At

#(dx)/(dy) = 1 + 1/( 1 + y^2 )

#y' = 1/(dx)/(dy). And so,

#the inclination of he tangent to the x-axis is

tangent

graph{(y-tan(x-y))((x-1.7654)^2+(y-1)^2-.01)((y-1) -2/3 (x-1.7654 ))=0[-10 6 -3 3]}