Fe2O3(s)+3CO(g)⟶2Fe(s)+3CO2(g) How many moles of Fe2O3 are necessary to produce 1.648 mol of CO2?

1 Answer
Jul 12, 2018

You have the stoichiometric equation...

Explanation:

Fe_2O_3(s) + 3CO stackrel(Delta)rarr2Fe(s) +3CO_2(g)

And to produce 1.648*mol CO_2 you need a THIRD of an equiv of "ferric oxide"...a mass of 1.648*molxx1/3xx159.69*g*mol^-1= "approx. 90 g"...