Question

Find a vector perpendicular to the plane `2*x-y+2z=5` ?

Answer 1

The Rqd. Vector is `(2,-1,2)`.

Explanation:

If the eqn. of a plane `pi` is `pi : ax+by+cz+d=0`, then, the the

vector `bot` to `pi`, called the normal vector of `pi` is the

vector `(a,b,c)`.

In our case, it is the vector `(2,-1,2)`.