Find all real numbers in the interval [0, 2pi) round to the nearest tenth? 3 sin^2x=sin x

1 Answer
Apr 17, 2018

x=0^c,0.34^c,pi^c,2.80^c

Explanation:

Rearrange to get:
3sin^2x-sinx=0

sinx=(1+-sqrt(1^2))/6

sinx=(1+1)/6 or (1-1)/6

sinx=2/6 or 0/6

sinx=1/3or0

x=sin^-1(0)=0, pi-0=0^c,pi^c
or
x=sin^-1(1/3)=0.34, pi-0.34=0.34^c,2.80^c

x=0^c,0.34^c,pi^c,2.80^c