# Find all zeros: f(x)=3x^7-32x^6+28x^5+591x^4-1181x^3-2810x^2+5550x-1125?

I don't have time to give a detailed explanation, but the zeroes are $x = 5$ (multiplicity 3), $x = - 3$ (multiplicity 2), and $x = \frac{5 \pm \sqrt{13}}{6}$ (each of multiplicity 1).