Find an equation for the circle centered at (4,-3) having radius at 2?

1 Answer
May 1, 2018

#(x-4)+(y+3)=4#

Explanation:

The standard equation of a circle is #(x-a)^2+(y-b)^2=r^2# where #(a,b)# is the center and #r# is the radius. Note the negatives for #a# and #b#
See link for more detail https://www.khanacademy.org/math/algebra2/intro-to-conics-alg2/standard-equation-circle-alg2/v/writing-standard-equation-of-circle

Therefore, the equation of the circle with center #(4,-3)# and radius #2# will be that:
#a=4#
#b=-3#
#r=2#
Thus, the equation is #(x-(4))^2+(y-(-3))^2=(2)^2# or simply:
#(x-4)^2+(y+3)^2=4#
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