Question

Find an equation for the circle centered at (4,-3) having radius at 2?

Answer 1

`(x-4)+(y+3)=4`

Explanation:

The standard equation of a circle is `(x-a)^2+(y-b)^2=r^2` where `(a,b)` is the center and `r` is the radius. Note the negatives for `a` and `b`
See link for more detail https://www.khanacademy.org/math/algebra2/intro-to-conics-alg2/standard-equation-circle-alg2/v/writing-standard-equation-of-circle

Therefore, the equation of the circle with center `(4,-3)` and radius `2` will be that:
`a=4`
`b=-3`
`r=2`
Thus, the equation is `(x-(4))^2+(y-(-3))^2=(2)^2` or simply:
`(x-4)^2+(y+3)^2=4`