Find #cos[tan^-1(5/12)-cot^-1(4/3)]# Find the value?

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Answer 1 · 2017-11-19T04:34:00

#cos[tan^-1(5/12)-cot^-1(4/3)]#

#=cos[tan^-1(5/12)-tan^-1(3/4)]#

#=cos[tan^-1((5/12-3/4)/(1+5/12xx3/4))]#

#=cos[tan^-1((-4/12)/(1+5/16))]#

#=cos[tan^-1(-1/3xx16/21)]#

#=cos[tan^-1(-16/63)]#

#=cos[sec^-1(sqrt(1+16^2/63^2))]#
#=cos[sec^-1(65/63)]#

#=cos[cos^-1(63/65)]#

#=63/65#