Find #lim_(x->oo) (6x+1)/abs(-2x+6)# algebraically?

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Answer 1 · 2017-10-25T03:15:11

#3#

We can disregard the constants in this, since it is a limit to infinity. So:

#(6x+1)/|-2x+6|#

#(6x)/|-2x|#

Cancelling #x#:

#(6)/|-2|=3#

So:

#lim_(x->oo)(6x+1)/|-2x+6|=3#