Question

Find sin(x) and cos(x) if tan(x)=-24/17 and the terminal side of (x) lies in quadrant II.?

Answer 1

Given

`tanx=-24/17` where `x in "quadrant II"`

Hence `sinx->+ve and cosx->"-ve"`

So `cosx=1/secx=-1/sqrt(1+tan^2x)`

`=-1/(sqrt(1+(-24/17)^2))=-17/sqrt865`

And `sinx=tanx xxcosx=24/sqrt865`