Question

Find the change in temperature if 1500 J of heat is added ?

Starting with 2.50 moles of Platinum. The specific heat of Platinum is 0.133J/GC.

Answer 1

See below

Explanation:

I think we first need to find the mass of 2.5 moles of Platinum

According to this periodic table (table 6)
`M(Pt)=195.08 gmol^-1`

Using the equation:

`n=(m)/(M)`

`2.5=(m)/(195.08)`

`m=487.7 g`

Now we must find the final temperature of the platinum using the following equation:

`Q=mcDeltaT`
`Q`=energy input (in this case, 1500J)
`m`=mass in grams , which is 487.7 grams in this case, which we found in step 1.
`c`= the specific heat capacity, in this case 0.133 J/gC.
`DeltaT`= the temperature change of the material, which is what we are interested in.

Let's plug everything in:
`1500=487.7 times 0.133 times DeltaT`
Hence:

`DeltaT=(1500)/(487.7 times 0.133)`

`DeltaT approx 23.1` degrees Celcius.