Find the coefficient of #x# in the expansion of #(1+x^2)(x/2-4/x)^6#. Can Anyone pls solve step by step with binomial formula?

1 Answer
Mar 12, 2018

#0#

Explanation:

Given:

#(1+x^2)(x/2-4/x)^6#

At first sight it might look like you will get a mixture of even and odd degree terms when this is multiplied out, but looking a little closer it becomes clear that this is not so.

In particular, note that:

#(1+x^2)(x/2-4/x)^6 = 1/x^6(1+x^2)(x^2/2-4)^6#

The right hand side only contains terms of even degree.

So the coefficient of #x# in the expansion is #0#