Find the complete integral of the equation (∂z/∂x_1)(∂z/∂x_2)(∂z/∂x_3)=z³x_1x_2x_3?
1 Answer
One solution is:
Explanation:
Symmetry suggests that separation of variables should result in a solution:
So let
....with corresponding results for
So the PDE now reads:
-
#X_1^' X_2^' X_3^' (X_1 X_2 X_3)^2 = (X_1 X_2 X_3)^3 \ x_1 x_2 x_3# -
#X_1^' \ X_2^' \ X_3^' = x_1 X_1 \ x_2 X_2 \ x_3 X_3 # -
#(X_1^')/(X_1 \ x_1) = ( x_2 X_2)/(X_2^') * (x_3 X_3)/(X_3^' #
This is the same statement as:
#f(x_1) = 1/(g(x_2)) * 1/(h(x_3)) qquad forall x_i #
These must be constant functions, or at very least they can be, so make an assumption or draw a conclusion:
#" where " C_1 = 1/(C_2 C_3)#
It follows that:
Integrating:
# X_1 = d_1e^( C_1\ x_1^2/2 )#
Pattern-matching:
#{(X_2 = d_2e^( C_2\ x_2^2/2 )),(X_3 = d_3e^( C_3\ x_3^2/2 )):}#
Validating this possible solution:
-
#partial_(x_1) z = C_1 x_1 \ d_1 \ e^(1/2( C_1 x_1^2 + C_2 x_2^2 + C_3 x_3^2 ))# -
#partial_(x_2) z = C_2 x_2 \ d_2 \ e^(1/2( C_1 x_1^2 + C_2 x_2^2 + C_3 x_3^2 ))# -
#partial_(x_3) z = C_3 x_3\ d_3 \ e^(1/2( C_1 x_1^2 + C_2 x_2^2 + C_3 x_3^2 ))#
And because, by separating the variables, a specific conclusion was drawn:
# C_1 = 1/(C_2 C_3)#
So, at least one solution exists. Whether or not it is the exact solution depends upon the boundary values.