Find the derivative of 3+2cosθ?

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Answer 1 · 2018-05-21T04:12:41

#-2sintheta#

I'm assuming that you're differentiating with respect to #theta#.

Given: #d/(d\theta)(3+2costheta)#.

#=d/(d\theta)3+d/(d\theta)(2costheta)#

#=0+2d/(d\theta)(costheta)#

We know that #d/dx(cosx)=-sinx# because it's a common derivative, so we get:

#=2*-sintheta#

#=-2sintheta#