Find the distance CD rounded to the nearest tenth. C=(5,6) and D=(2,2) ?

Feb 16, 2018

ved(CD) = color(green)(5

Explanation:

Distance between two points given by the formula

$d = \sqrt{{\left(x 2 - x 1\right)}^{2} + {\left(y 2 - y 1\right)}^{2}}$

$\vec{C D} = \sqrt{{\left(5 - 2\right)}^{2} + {\left(6 - 2\right)}^{2}}$

$\vec{C D} = \sqrt{{3}^{2} + {4}^{2}} = \sqrt{25}$

=> color(green)(5

Feb 16, 2018

$C D = 5$

Explanation:

Use the Distance Formula:

$d = \sqrt{{\left({x}_{2} - {x}_{1}\right)}^{2} + {\left({y}_{2} - {y}_{1}\right)}^{2}}$

1. Plug into formula
$d = \sqrt{{\left(5 - 2\right)}^{2} + {\left(6 - 2\right)}^{2}}$

2. Solve
$d = \sqrt{{\left(3\right)}^{2} + {\left(4\right)}^{2}}$
$\implies d = \sqrt{9 + 16}$
$\implies d = \sqrt{25}$
$\implies d = 5$