Question

Find the distance CD rounded to the nearest tenth C=(6,-5) and D=(-1,-4) ?

Answer 1

`\overline{CD} =7.1`

Explanation:

Let's say, `(x_1, y_1)\ \ \ \ \ \text{and}\ \ \ \ \ (x_2, y_2)` are two points in a `xy` plane. We can find the shortest distance between two point by applying the distance formula stated as:

`\text{Distance}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}`

So by putting our given points `(x_1, y_1)=(6, -5)` and `(x_2, y_2)=(-1,-4)` in the distance formula, we have:

`\overline{CD} = \sqrt{(-1-6)^2+(-4-(-5))^2}`

Simplify to get:

`=5\sqrt{2}`