Find the equation of a line that passes through the point (5,-1) and has a slope equal to tan 135 degrees?

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Answer 1 · 2018-05-18T03:25:32

#y=-x+4#

.

#tan135^@=sin135^@/(cos135^@)=sin45^@/(-cos45^@)=(sqrt2/2)/(-sqrt2/2)=-1#

The equation of a straight line is:

#y=mx+b# where #m# is the slope and #b# is the #y#-intercept.

#y=-x+b#

We can solve for #b# by plugging in the coordinates of the point on the line:

#-1=-5+b#

#b=4#

Therefore, the equation is:

#y=-x+4#