Find the equation of a line that passes through the point (5,-1) and has a slope equal to tan 135 degrees?

1 Answer
May 18, 2018

y=-x+4y=x+4

Explanation:

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tan135^@=sin135^@/(cos135^@)=sin45^@/(-cos45^@)=(sqrt2/2)/(-sqrt2/2)=-1tan135=sin135cos135=sin45cos45=2222=1

The equation of a straight line is:

y=mx+by=mx+b where mm is the slope and bb is the yy-intercept.

y=-x+by=x+b

We can solve for bb by plugging in the coordinates of the point on the line:

-1=-5+b1=5+b

b=4b=4

Therefore, the equation is:

y=-x+4y=x+4