Find the equation of the tangent line to the function at a given point f(x)=e^-3x+1 ; (0,e)?

1 Answer
Jan 21, 2018

y-e=-3e(x-0).

Explanation:

From the given point I'm assuming the function is f(x)=e^(-3x+1) which contains the point (0,e).

Using the Chain Rule on f(x) we have:

f'(x) = e^(-3x+1)*(-3)

So f'(0) = -3e.

The equation of the line can be written in point-slope form:

y-e=-3e(x-0).

This can be rewritten as y=-3e*x+e