Find the equation of the tangent line to the graph of $y = sin2(πx3/6)$ at the point with $x = 1$ ?

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Answer 1 · 2018-02-26T12:42:21

Equation of tangent at $x=1)$ is $y= -pi(x-1)$

$y=sin 2(pi x 3/6)=sin (pi x )$ . At $x=1$

$y(1)= sin pi =0 :.$ The point is $(1,0)$

$y=sin(pi x):.$ Derivative $y'= pi cos( pi x)$

At $x=1$ the slope is $m=y'= pi cos (pi) = -pi$

So equation of tangent at point $(1,0)$ in point slope form is

$y-0= m(x-1) or y= -pi(x-1)$

Find the equation of the tangent line to the graph of y = sin2(πx3/6)y = sin2(πx3/6) at the point with x = 1x = 1?