Find the exact value of sin^3 3645° Do I go around the circle 10 times? is there an easier way to do this?

2 Answers
Mar 29, 2015

The first thing to note is that, everytime you add one revolution(ie #360# or #2pi#) to an angle you get back to the same angle.

Example: #30°# and #30 + 360° = 390°#
is one and the same angle!
So

Step 1:
Find the number of "#360°s#" there are in that angle, that is; the number of times that angle comes back to the same(duuh).
Do: #3645/360 = 10.125#
This means that you turned round the spot at least #10# times!

Step 2:
Now. After turning around you come back to the original angle: #3645 - 10*360 = 3645 - 3600#
# = 45#

Step 3:
#sin^3(3645) = sin^3(45)#
#= (1/sqrt(2))^3#
# = 1/(2sqrt(2))#

Mar 29, 2015

One way to get this is to "go around the circle 10 times" for #3600^@# Then go another #45^@#

Or, understanding that that's what you could do, you could ignore the whole number multiple of #360^@# and just "go to" #45^@#

Or, think less geometrically, use the fact that #sin(A) = sin(A+360^@*n)# for any integer #n#. In this case #n=10#. This amounts to the same thing as "ignoring that #3600^@#

In technical terms: an angle of #3645^@# is co-terminal with an angle of #45^@#. So #sin(3645^@)= sin(45^@)= sqrt2/2#

#sin^3(3645^@)=(sin(3645^@))^3=(sqrt2/2)^3=(2sqrt2)/8=sqrt2/4#