Find the general solution of #x(dx/dt) =t+2# ?

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Answer 1 · 2018-05-19T06:58:24

The general solution is #x=+-sqrt(t^2+4t+2C)#

This is a first order separable differential equation

#x(dx/dt)=t+2#

#xdx=(t+2)dt#

#intxdx=int(t+2)dt#

#x^2/2=t^2/2+2t+C#

#x^2=t^2+4t+2C#

#x=+-sqrt(t^2+4t+2C)#