# What is the derivative of y=e^(3-2x) ?

$y ' = - 2 {e}^{3 - 2 x}$.
Exponential Rule: $\left({e}^{x}\right) ' = {e}^{x}$
Chain Rule: $\left[f \left(g \left(x\right)\right)\right] ' = f ' \left(g \left(x\right)\right) \cdot g ' \left(x\right)$
Since $f \left(x\right) = {e}^{x}$ and $g \left(x\right) = 3 - 2 x$, we have
$y ' = {e}^{3 - 2 x} \cdot \left(- 2\right) = - 2 {e}^{3 - 2 x}$