Find the indicted values of f; (B) graph f and label the points from part A , If they exist , and (C) find the domain, range and values of x in the domain of f at which f is discountinous ?

1 Answer
bp
Oct 1, 2017

f(-2)=-2, f(1)=1, f(2)=0
Domain [-2,2]
Range [-2,1]
Discontinuity at x=1

Explanation:

At x=-2, the piece wise function is represented by f(x)=x, hence f(-2) would be -2

At x=1, the piece wise function is represented by f(x)= -x+2, hence f(1) would be -1+2= 1

At x=2, the piece wise function is represented by f(x)= -x+2, hence f(2) would be 2+2=0 .

None of the options given represent f(x). The graph of f(x) has been drawn as shown below. The graph in pink pen represents f(x)=x and the graph in white pen represents f(x)= -x+2.
The domain is [-2,2] and range is [-2,1]
enter image source here

f(x) is discontinuous at x=1

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