Question

Find the integration of ∫ [1-2(x^2)]dx limit from 0 to 1?

Answer 1

`int_0^1 (1-2x^2)dx =1/3`

Explanation:

`I = int_0^1 (1-2x^2)dx`

Apply linearity

`I = int_0^1 1 dx - 2 int_0^1 x^2 dx`

Apply power rule to both terms

`I = x|"_0^1 - 2* x^3/3|_0^1`

`= 1 - 2/3 = 1/3`