Find the perimeter of the triangle with vertices (−2,2), (0,4), and (1,−2)?

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Answer 1 · 2018-06-22T15:53:17

Perimeter #color(green)(= 6.08 + 5 + 2.83 = 13.91#

#A(-2,2), B(0,4), C(1,-2)#

#a = sqrt((0-1)^2+(4+2)^2) = 6.08#

#b = sqrt((1+2)^2+(-2-2)^2) = 5#

#c = sqrt((-2-0)^2+(2-4)^2) = 2.83#

Perimeter #color(green)(= 6.08 + 5 + 2.83 = 13.91#

Answer 2 · 2018-06-22T15:56:31

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