Find the sum of 5-7+8-9+11-11+14-13 up to 20 terms?

1 Answer
May 15, 2018

#25#

Explanation:

Given the series:

#5-7+8-9+11-11+14-13+...#

Note that the odd terms are:

#5, 8, 11, 14,...#

which is an arithmetic sequence with initial term #5# and common difference #3#.

The #10#th term of this subsequence is #5+3(10-1) = 5+27 = 32# and the sum to #10# terms is hence:

#10 * (5+32)/2 = 185#

Meanwhile, the even terms are:

#-7, -9, -11, -13,...#

which is an arithmetic sequence with initial term #-7# and common difference #-2#.

The #10#th term of this subsequence is #-7-2(10-1) = -25# and the sum to #10# terms is hence:

#10 * (-7+(-25))/2 = -160#

So the sum of both subsequences is #185-160 = 25#

Alternatively (and as a check), note the result of combining pairs of terms of the original sequence:

#5-7+8-9+11-11+14-13+... = (-2)+(-1)+0+1+...#

which is an arithmetic series with initial term #-2# and common difference #1#.

The #10#th term of this series is #-2+1(10-1) = 7# and the sum to #10# terms is hence:

#10 * ((-2)+7)/2 = 25#