Find the value of x given that [x combination 4]=5[(x-2) combination 3]?

1 Answer

There appears to be two values.
#x=5, 16#

Explanation:

The combination formula is

#C_(n,k)=(n!)/((k!)(n-k)!)# with #n="population", k="picks"#

We're being asked to find a value #x# such that:

#C_(x,4)=5C_(x-2,3)#

#(x!)/((4!)(x-4)!)=((5)(x-2)!)/((3!)(x-2-3)!)#

#(x!)/((24)(x-4)!)=((5)(x-2)!)/((6)(x-5)!)#

#(x (x-1) (x-2)(x-3)(x-4)!)/((24)(x-4)!)=((5)(x-2)(x-3)(x-4)(x-5)!)/((6)(x-5)!)#

#(x (x-1) (x-2)(x-3))/(24)=((5)(x-2)(x-3)(x-4))/(6)#

#(6)x (x-1) (x-2)(x-3)=(24)(5)(x-2)(x-3)(x-4)#

#x (x-1) =(4)(5)(x-4)#

#x^2-x =20x-80#

#x^2-21x+80 =0#

#(x-5)(x-16)=0#

#x=5, 16#

Checking the answer:

#(5!)/((4!)(5-4)!)=((5)(5-2)!)/((3!)(5-2-3)!)#

#5=((5)(3!))/((3!)(0!))=5color(white)(000)color(green)root#

#(16!)/((4!)(16-4)!)=((5)(16-2)!)/((3!)(16-2-3)!)#

#(16!)/((4!)(12!))=((5)(14!))/((3!)(11!))#

#(16xx15xx14xx13)/24=((5)(14xx13xx12))/6#

#(16xx15xx14xx13)=(20)(14xx13xx12)#

#43,680=43,680color(white)(000)color(green)root#