Find the values of x for all points on the graph of f(x) = x^3-2x^2+5x-16 where the slope of tangent is 4?
1 Answer
Apr 1, 2018
Explanation:
#"note that slope of tangent is given by "f'(x)#
#"equating "f'(x)" to 4 and solving gives x-coordinates"#
#rArrf'(x)=3x^2-4x+5=4#
#"solve "3x^2-4x+1=0#
#rArr(3x-1)(x-1)=0#
#rArrx=1/3" and "x=1#
#"are the x-coordinates where slope of tangent is 4"#
