Question

Find the volume of the gas at NTP by treating 200gm of CaCO3 with excess of dil Hcl?

Answer 1

`V~=48*L`

Explanation:

We address the stoichiometric equation....

`CaCO_3(s) + 2HCl(aq) rarr CaCl_2(aq) + CO_2(g)uarr + H_2O(l)`

And thus moles of calcium carbonate is equivalent to the moles of carbon dioxide gas evolved....

Now `"NTP"` specifies a pressure of `1*"bar"` (`0.987*atm`) and a temperature of `293.15*K`, and the molar volume is `24.05*L`...

With respect to calcium carbonate we gots a molar quantity of....

`(200*g)/(100.09*g*mol^-1)=2*mol`

And thus we gots a `2*mol` quantity of carbon dioxide evolved...the which expresses a volume of `2*molxx24.05*L*mol^-1=??L`