Find value(s) c ∈ (−2, 4) such that f'(c) is parallel to the chord line joining ?

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Im not sure wich Theorem they mean :/

1 Answer
Mar 30, 2018

Mean Value Theorem
If a function #f# is continuous on #[a,b]# and differentiable on #(a,b)#,
then there exists c in #(a,b)# such that #f'(c)={f(b)-f(a)}/{b-a}#.

Explanation:

You can learn more about the theorem here: https://socratic.org/calculus/graphing-with-the-first-derivative/mean-value-theorem-for-continuous-functions

In this particular question, #f# is continuous on #[-2,4]#, but not differentiable on #(-2,4)# because the derivative does not exist at #1/2#.

In this case there is no point in the interval at which the tangent line is parallel to the secant line (chord).