Question

Find `x` in degrees radians (either one is fine)? `tanxsinx-tanx=0` Thanks in advance

So I think you're supposed to factor the `tanx` first, so `tanx` would equal `0` and `sinx-1=0`... but my final answer isn't right...

I know the answer is `0` and `pi` (that's in radians)

Answer 1

Well...since you have a good idea of the problem, let's see where you made a mistake

Explanation:

Given problem:
`tanxsinx-tanx=0`

1.Factoring as you did:
`tanx(sinx-1)=0`

1. Set factors equal to 0, as you did:
   `tanx=0`
   `sinx=1`

2. Solutions in the interval `[0,2pi)` which seems like what you were trying to find:
   `x=0, pi` for `tanx=0`
   `x=pi/2` for `sinx=1`

3. Now `x=pi/2` is not a solution because tangent is undefined at `pi/2` which is likely why your final answer has one extra solution

4. Graph

graph{tanxsinx-tanx [-3.352, 4.11, -0.995, 2.735]}