For a sine function with amplitude A=0.75 and period T=10, what is y(4)?

I'm so confused, please help!! It's for my AP Physics summer assignment, and I haven't learned this yet.

1 Answer
Jun 28, 2018

y(4)=0.033

Explanation:

.

The general form of a sine function is:

y=asin(bx+c)

where a is the amplitude, b is the coefficient of the angle, and c is the phase shift.

To find the period of the function, we have to divide the regular period of a sine function, which is 2pi, by the coefficient of the angle.

Therefore, the period of the above general sine function would be:

(2pi)/b.

In this problem, the period is given as T=10. This means:

(2pi)/b=10

2pi=10b

b=pi/5

If we assume there is no phase shift. i.e. c=0 then our sine function would be:

y=0.75sin(pi/5x)

y(4)=0.75sin(pi/5(4))

y(4)=0.75sin((4pi)/5)=0.75(0.044)=0.033