For an ideal gas, how do you calculate the pressure in atm if #8.25 x 10^-2# mol occupies 174 mL at 215°C?

1 Answer
May 9, 2016

Answer:

#P=(nRT)/V=??*atm#

Explanation:

We have been quoted the moles, #n#, the temperature, #488*K# on the absolute scale, the volume, #0.174*L#. All we need to do is choose an appropriate gas constant. #R=0.0821*L*atm*K^-1*mol^-1#.

Thus, #P=(8.25xx10^-2*molxx0.0821*(L*atm)/(K*mol)xx488*K)/(0.174*L)# for an answer in atmospheres.

Thx to Shelby who pointed out an error on my part!