Question

For an ideal gas, how do you calculate the pressure in atm if `8.25 x 10^-2` mol occupies 174 mL at 215°C?

Answer 1

`P=(nRT)/V=??*atm`

Explanation:

We have been quoted the moles, `n`, the temperature, `488*K` on the absolute scale, the volume, `0.174*L`. All we need to do is choose an appropriate gas constant. `R=0.0821*L*atm*K^-1*mol^-1`.

Thus, `P=(8.25xx10^-2*molxx0.0821*(L*atm)/(K*mol)xx488*K)/(0.174*L)` for an answer in atmospheres.

Thx to Shelby who pointed out an error on my part!