For every pair of numbers a and b, the function f satisfies b^2 f(a) = a^2 f(b). If f(2) does not equal 0, find the value of [f(5) - f(1)] / f(2)?
2 Answers
Jun 2, 2017
Explanation:
Given:
b^2f(a) = a^2f(b)
Let
Then, putting
4f(a) = a^2*f(2) = 4ka^2
Dividing both ends by
f(a) = ka^2
So:
(f(5)-f(1))/f(2) = (k*5^2-k*1^2)/(k*2^2) = (25-1)/4 = 6
Jun 2, 2017
Explanation:
Making
NOTE: