Question

For `f(m)=3m^2-5`, how do you find f(4),f(-3),f(6)?

Answer 1

`f(4) = 43`
`f(-3) = 22`
`f(6) = 102`

Explanation:

Given `f(color(red)(m))=3color(red)(m)^2-5`

To evaluate `f(color(red)()4)` rewrite the given equation replacing each `color(red)(m)` with `color(red)(4)` and perform the arithmetic.
`color(white)("XXXX")` `f(color(red)(4)) = 3(color(red)(4))^2 -5`
`color(white)("XXXX")` `color(white)("XXXX")` `=3(16)-5`
`color(white)("XXXX")` `color(white)("XXXX")` `= 43`

Similarly for `f(color(red)(-3))`
`color(white)("XXXX")` `f(color(red)(-3)) = 3(color(red)(-3))^2-5`
`color(white)("XXXX")` `color(white)("XXXX")` `=3(9)-5`
`color(white)("XXXX")` `color(white)("XXXX")` `= 22`

and for `f(6)`
`color(white)("XXXX")` `f(color(red)(6)) = 3(color(red)(6))^2-5`
`color(white)("XXXX")` `color(white)("XXXX")` `=3(36)-6`
`color(white)("XXXX")` `color(white)("XXXX")` `= 102`