For #h(x)=x^4 -3#; how do you find f(4),f(-3),and f(6)?

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Answer 1 · 2015-07-27T12:38:48

You simply evaluate the function for #x=4#, #x=-3#, and #x=6#.

Your function looks like this

#h(x) = x^4 - 3#

In order to find the value of #h# in points #4#, #-3#, and #6#, evaluate the function for these three values of #x#.

Simply put, replace #x# with these numbers and calculate #h#.

#h(4) = color(blue)(4)^4 - 3 = 256 -3 = color(green)(253)#

#h(-3) = color(blue)((-3))^4 - 3 = 81 - 3 = color(green)(78)#

and finally

#h(6) = color(blue)(6)^4 - 3 = 1296 - 3 = color(green)(1293)#