# For h(x)=x^4 -3; how do you find f(4),f(-3),and f(6)?

##### 1 Answer
Jul 27, 2015

You simply evaluate the function for $x = 4$, $x = - 3$, and $x = 6$.

#### Explanation:

Your function looks like this

$h \left(x\right) = {x}^{4} - 3$

In order to find the value of $h$ in points $4$, $- 3$, and $6$, evaluate the function for these three values of $x$.

Simply put, replace $x$ with these numbers and calculate $h$.

$h \left(4\right) = {\textcolor{b l u e}{4}}^{4} - 3 = 256 - 3 = \textcolor{g r e e n}{253}$

$h \left(- 3\right) = {\textcolor{b l u e}{\left(- 3\right)}}^{4} - 3 = 81 - 3 = \textcolor{g r e e n}{78}$

and finally

$h \left(6\right) = {\textcolor{b l u e}{6}}^{4} - 3 = 1296 - 3 = \textcolor{g r e e n}{1293}$