# For P(x)=3x^2-2x; how do you find P(0),P(-2) and P(3)?

Jul 15, 2015

Given an equation defined with a variable place holder (in this case $x$), replace the variable place holder with specified value and evaluate to determine the value of the equation at that point.

#### Explanation:

If $P \left(\textcolor{red}{x}\right) = 3 {\textcolor{red}{x}}^{2} - 2 \textcolor{red}{x}$

then

$P \left(\textcolor{red}{0}\right) = 3 {\left(\textcolor{red}{0}\right)}^{2} - 2 \left(\textcolor{red}{0}\right) = 0$

$P \left(\textcolor{red}{- 2}\right) = 3 {\left(\textcolor{red}{- 2}\right)}^{2} - 2 \left(\textcolor{red}{- 2}\right) = 12 + 4 = 16$

$P \left(\textcolor{red}{3}\right) = 3 {\left(\textcolor{red}{3}\right)}^{2} - 2 \left(\textcolor{red}{3}\right) = 27 - 6 = 21$