For the equilibrium, CO_(s)+CO2_(g)--->2CO_(g), Kp=63atm at 1000K.If at equilibrium Pco=10Pco2 then total pressure at equilibrium is?

1 Answer
Ernest Z.
Dec 12, 2017

At equilibrium, #p_text(tot) = "6.9 atm"#.

Explanation:

#"C(s)" + "CO"_2"(g)" → "2CO(g)"; K_text(p) = 63#

#K_text(p) = p_text(CO)^2/p_text(CO₂) = (10p_text(CO₂))^2/p_text(CO₂) = (100p_text(CO₂)^color(red)(cancel(color(black)(2))))/color(red)(cancel(color(black)(p_text(CO₂)))) = 100p_text(CO₂) = 63#

#p_text(CO₂) = 63/100color(white)(l) "atm" = "0.63 atm"#

#p_text(CO) = 10p_text(CO₂) = "10 × 0.63 atm = 6.3 atm"#

#p_text(tot) = p_text(CO₂) + p_text(CO) = "0.63 atm + 6.3 atm = 6.9 atm"#

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