Question

For the following reaction: BaO+H2SO4--> BaSO4 +H2O;(Assume that the other reactant is in excess) a) How much BaSO4 can be formed from 196 g of H2SO4 b) If 81 g of water is formed during this reaction, how much BaO was used?

Answer 1

a) You can form 466 g of BaSO₄.
b) 690 g of BaO was used.

The balanced equation is

BaO + H₂SO₄ → BaSO₄ + H₂O

a) Mass of BaSO₄

`196 cancel("g H₂SO₄") × (1 cancel("mol H₂SO₄"))/(98.08 cancel("g H₂SO₄")) × (1 cancel("mol BaSO₄"))/(1 cancel("mol H₂SO₄")) × "233.39 g BaSO₄"/(1 cancel("mol BaSO₄")) = "466 g BaSO₄"`

b) Mass of BaO

`81 cancel("g H₂O") × (1 cancel("mol H₂O"))/(18.02 cancel("g H₂O")) × (1 cancel("mol BaO"))/(1 cancel("mol H₂O")) × "153.33 g BaO"/(1 cancel("mol BaO")) = "690 g BaO"`